The example shown at right illustrates this: Upon hitting the shock absorber, a load of 10 lbs. is traveling at a final velocity of 80 inches/second. It must be brought to rest over the shock absorber stroke of 0.50 inches. To determine the Mz and g forces on the carrier at this point: Mz = moment about z-axis V = velocity (final) a = deceleration rate g = 386.4 in/sec^{2} (standard gravity) s = shock stroke a = v_{f}^{2} __(80 in/sec)__^{2} = 6400 in/sec^{2} (decel rate) 2s 2 x 0.50 in. force equiv. = __a__ x L = __6400 in/sec__^{2} x 10 lbs = 165.6 lbs g 386.4 in/sec^{2} Therefore the Mz created during stopping is: Mz = (force ea) x L = 165.6 lbs x 12 in. = 1987.2 in-lbs |